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Ecolint Campus des NationsMathematics
Ecolint Campus des NationsMathematics
Year 8 · Statistics

Solutions · Full Answer Key

Pack A answers · Pack B answers · Problem-solving worked solutions

Pack A — Answers

Bronze
1.15
2.15
3.15
4.11
5.7
6.25\dfrac{2}{5}
7.(a) 7.6 (b) 8 (c) 8
8.17
9.30 — much larger than the rest
10.10
11.Survey: a study collecting data from some or all of a group. Census: data from every member of a population. Population: the entire group of interest. Sample: a subset of the population studied.
12.Population: 600 students; Sample: 30 students
13.Simple random sampling
14.10%
15.60 students
16.Leading question — assumes the food is poor
17.520
18.Self-selection bias: library users read more than average
19.24%
20.Early arrivers are not representative — they may live near school or be more punctual
21.Pie chart
22.Bar chart
23.Line chart
24.Histogram
25.144°
26.151.2°
27.42%
28.2 students
29.22°C at 3 pm
30.9.5 cm
31.The extent to which data values are scattered around a central value
32.(a) 7.8 (b) 8
33.Roughly symmetric
34.Positive (right) skew
35.Negative (left) skew
36.50
37.Left tail: values below the centre; right tail: values above
38.Flat (all bars same height)
39.Symmetric (peak at 5)
40.2
Silver
41.13.5
42.15
43.Mean 10, median 9
44.2.08 (sum 25, count 12)
45.23
46.Mean 7.25, median 7, mode 7
47.Mean 7, median 7
48.Frequencies: 0→3, 1→4, 2→2, 3→1; mode = 1
49.35
50.Mean changes most; median changes slightly; mode unchanged (no mode either way)
51.Year 7: 20, Year 8: 18, Year 9: 22
52.55% — moderately confident with n=200
53.Stratified random sample by class/gender, sample size ≥ 50; use anonymous questionnaire
54.(a) census; (b) systematic sample (random-ish); (c) biased
55.Not necessarily — small sample (n=30), one class only (may be selected by ability or homeroom).
56."How often do you eat the cafeteria food?" with options: never / 1-2 times/week / 3-4 / 5+
57.45% is much higher than 10% — sample likely not representative or class is special
58.Trip participants are self-selected (only those whose parents allow it, those who can afford it); often a single year-group.
59.(d) Stratified across year-groups
60.1500 is impossible (15 m) — likely a typo for 150 or 155. Remove or correct.
61.20
62.14
63.(a) 3 (b) ≈ 2.33
64.Red 31.6%, Blue 47.4%, Green 21.1% (total 38)
65.3, 5, 6, 1
66.(a) 240 (b) 60 (c) Apr
67.60
68.6
69.(a) 162 (b) Friday (50)
70.200
71.(a) 8.8 (b) 8 (c) 2.8
72.Class 1 faster; Class 2 more consistent
73.Positive skew
74.Median 10. 30 likely an outlier (large gap from 15)
75.(a) 2.4 (b) 8
76.Set B (larger range)
77.(a) 3.5 (b) 1.5
78.Class B (smaller SD)
79.Wrong — mean alone doesn't imply concentration. Need spread to judge.
80.B — much lower SD
Gold
81.(a) 16.25 cm (b) 15.5 cm (c) 18 cm
82.28 — 5 cm above next-highest 23; largest gap in data
83.x=6x = 6
84.20
85.87
86.17
87.2
88.≈75\approx 75 (mean = (75×5+150)/7≈75(75 \times 5 + 150)/7 \approx 75)
89.75
90.(a) 2.875 (b) 10 (c) 2
91.Y7: 20, Y8: 18, Y9: 22, Y10: 10, Y11: 10
92.Estimate ≈ 6.5 h; n = 30 is small with range 4 → moderate confidence
93.n≈1067n \approx 1067 — practically impossible; full census is needed
94.(a) 65% (b) 390 (c) Margin ≈ 9% — could be 56–74% in the wider group
95.Forces a choice between only two options; what about no pets / neither / both equally? Improvement: "Which do you prefer: cats / dogs / both equally / neither?"
96.(i) is better — random; (ii) introduces selection bias (early arrivers).
97.Method A: random call list. Pro: random; Con: phone bias. Method B: fitness-app users. Pro: large data; Con: heavily biased (active users only).
98.Overlap: 10 is in both (c) and (b); the upper limit of (b) should be 9 or 9.99.
99.≈ 4.7 distinct names
100.Not particularly biased — Likert scale; balanced 5 options.
101.(a) 12-15 (b) 20
102.A is stronger in Maths but weaker in English; both similar in Science
103.(a) 90°, 126°, 108°, 36° (b) 90, 126, 108, 36
104.Maths 144°, English 108°, Science 72°, Other 36°
105.Densities 3, 5, 3, 1. Tallest bar = class 2 (density 5)
106.(a) 1520 (b) 700 (c) April (+400)
107.200, 180, 220
108.Grouped bar — places boys and girls side by side for each year
109.(a) 200 (b) 90°
110.(c) — truncated axis makes 50 vs 50 look very different
111.(a) 12.5 (b) 19.5 (c) 7
112.Fences 2 and 30; no formal outliers
113.(a) B (b) B (IQR 9 vs 6) (c) B (Q3 - median = 6 > median - Q1 = 3 → positive skew)
114.First: symmetric. Second: positive skew (long upper tail pulls mean above median).
115.≈ 75.8
116.A: most employees within £45–55k; B: wider spread, fewer "typical" employees
117.(a) 13 (b) 50 is outlier (upper fence = 47.5)
118.(a) Positive skew (b) A few very wealthy households pull the mean above the median
119.No — could be: changing student ability; different exam; smaller class with outliers
120.A: mean 12.12, range 0.3 (consistent). B: mean 12.24, range 1.0 (variable).
Platinum
121.Mean ≈ 15.63; median = 15
122.Combined mean ≈73.75\approx 73.75; combined median cannot be deduced without raw data.
123.E.g. 9, 9, 11, 12, 16, 15 — check.
124.15.5
125.E.g. 1, 4, 4, 5, 7, 9, 12 — check: sum 42 ✓, median 5 ✓, mode 4 ✓, range 11 ✗ — adjust to 1, 4, 4, 5, 7, 11, 10 (sort 1, 4, 4, 5, 7, 10, 11; mean 42/7 = 6 ✓; mode 4 ✓; median 5 ✓; range 10 ✗). Try 2, 4, 4, 5, 8, 8, 11: median 5 ✓; mode 4 ✓; sum 42; range 9 ✓.
126.(a) +100 to all (b) Mode disappears; mean and median may decrease (c) ×2 to all
127.Largest = 15. Example set: 9, 10, 12, 14, 15.
128.a=8a = 8
129.n=15n = 15
130.E.g. 6, 7, 7, 7, 7, 8 (mean 42/6 = 7, median 7, mode 7, range 2).
131.Pure stratified gives Y7: 20, Y8: 20, Y9: 20, Y10: 10, Y11: 10. Both Y10 and Y11 already get 10, > 5. So sample sizes: 20, 20, 20, 10, 10.
132.Estimate mean ≈ 18 kg; high spread (range 30 kg → many breeds → mean less informative)
133.95% confident the true support is 48–54%. Cannot rule out A being below 50% (i.e. losing).
134.200/300 = 67% (among respondents); could overestimate if pet owners more likely to respond.
135.Selection (only gate-passers), non-response (refusers), social desirability (under-reporting). Reduce by random in-class survey + anonymity.
136.90/100 = 90%? No — recompute using stratified weights.
137.Sample = 1 class, not the school. Cannot generalise without further sampling.
138.95% confident the true population proportion lies in 30–40%. Does NOT mean any individual has 30–40% chance of liking pizza.
139."How many days per week do you exercise for at least 30 min? 0/1-2/3-4/5-6/7" — stratified random sample across years.
140.Investigate zeros (absences? actual zeros?). 100 is plausible (perfect score). Missing entries: contact source or exclude. Document changes.
141.(a) 3, 5, 3, 1 (b) Density-5 class
142.Plane 48.4%, Train 9.3%, Car 100%; bar chart is best
143.Salaries 12000/180°, Rent 6000/90°, Supplies 3600/54°, Other 2400/36°
144.A: +5, B: +2, C: -2. Trend: A improved most; C declined.
145.(a) ≈ 37.1% (b) ≈ 3.25/year
146.(a) Fine — equal slices for 4 equal-frequency categories. (b) Each category 25% of the whole.
147.Y-axis doesn't start at 0 — visual difference exaggerated. Fix: start at 0.
148.Frequencies: 2, 6, 16, 18, 8 (total 50)
149.Show monthly line + a horizontal mean line. Add range and standard deviation.
150.Bar chart easier; pie chart accurate but slices hard to compare exactly
151.SD ≈ 4.42 cm
152.Mean dropped 0.62; median dropped 0.5. Median is more robust to outliers.
153.15.2 cm
154.(a) 174 ms (b) Cannot be negative — extrapolation error
155.A symmetric, B asymmetric. A IQR 10; B IQR 16. B has heavier upper-tail.
156.Q1 = 70, Q3 = 85, IQR = 15. Fences: 47.5 and 107.5.
157.(a) 240 (b) 156
158.n=9n = 9
159.(a) 80 (b) 40 (c) 30
160.Densities 3, 5, 3, 1; modal bar = density 5

Pack B — Answers

Bronze
1.14
2.19
3.14
4.14
5.6
6.415\dfrac{4}{15}
7.(a) 6 (b) 6 (c) 4
8.25
9.20 — much larger
10.14
11.Same definitions.
12.Population: 800; Sample: 25
13.Random sampling (drawing names)
14.8%
15.75 students
16.Leading question — assumes more sports lessons are good
17.420
18.Selection bias: football players favour football
19.30%
20.Bus users are biased — exclude walkers
21.Pie chart (or stacked bar)
22.Bar chart
23.Line chart
24.Histogram
25.108°
26.100.8°
27.28%
28.4 students
29.19°C at 3 pm
30.17.5 cm
31.Same.
32.(a) 10 (b) 10
33.Same.
34.Same.
35.Same.
36.80
37.Same.
38.Same.
39.Symmetric (peak at 3)
40.2.8
Silver
41.16.5
42.13
43.Mean 11, median 10
44.5 (sum 50, count 10)
45.18
46.Mean 14.86, median 14, mode 12
47.Mean 13.5, median 13.5
48.Same.
49.42
50.Same idea
51.Same.
52.50% — similar
53.Same logic
54.Same.
55.Same.
56."What is your view on phones in school? Options: Allow / Restrict / Ban."
57.8% is close to 10% — consistent
58.Same.
59.Same.
60.220°C impossible for room temperature; correct to 22.
61.30
62.16
63.(a) 3 (b) ≈ 0.67
64.Red 37.5%, Blue 50%, Green 12.5% (total 40)
65.2, 3, 4, 1
66.(a) 260 (b) 65 (c) Apr
67.Same.
68.4
69.(a) 143 (b) Friday (45)
70.220
71.(a) 7 (b) 6 (c) 3.2
72.Same.
73.Negative skew
74.Median 10. 25 likely an outlier (gap from 13)
75.(a) 2.4 (b) 8
76.Same.
77.(a) 7 (b) 3
78.Same.
79.Same.
80.Same.
Gold
81.Same.
82.Same.
83.x=7x = 7
84.30
85.100
86.22.5
87.3
88.≈80.7\approx 80.7
89.73
90.(a) 1.75 (b) 10 (c) 2
91.Apply 1/10 to each.
92.Estimate 7.0 h; better confidence with n = 50
93.n≈400n \approx 400
94.(a) 65% (b) 520 (c) Margin ≈ 7%
95.Same.
96.Same.
97.Same.
98.Same.
99.Same.
100.Same.
101.Same.
102.Same observation.
103.(a) 72°, 144°, 108°, 36° (b) 48, 96, 72, 24
104.Maths 150°, English 105°, Science 75°, Other 30°
105.Same.
106.Same.
107.Same.
108.Same.
109.(a) 210 (b) 126°
110.Same.
111.Same.
112.Same.
113.Same.
114.Same.
115.≈ 66.2
116.Same.
117.Same.
118.Same.
119.Same.
120.Same.
Platinum
121.Same.
122.Same.
123.Similar reasoning.
124.14.33
125.Similar.
126.Same.
127.Same.
128.a=3a = 3
129.n=20n = 20
130.Same.
131.Same.
132.Same.
133.Same.
134.Same.
135.Same.
136.Same.
137.Same.
138.Same.
139.Same.
140.Same.
141.Same.
142.Same.
143.Salaries 7200/144°, Rent 5400/108°, Supplies 3600/72°, Other 1800/36°
144.Same.
145.Same.
146.Same.
147.Same.
148.Same.
149.Same.
150.Same.
151.Same.
152.Same.
153.Same.
154.Same.
155.Same.
156.Same.
157.Same.
158.Same.
159.Same.
160.Same.

Problem-solving — Worked Solutions

1Problem 1
Answer
(a) 16.25 cm (b) 15.5 cm (c) 17 cm (d) 18 cm (e) 28 — large gap from the rest
Full working
(a) Sum 325, n=20n = 20. Mean =16.25= 16.25 cm.

(b) Sorted, the 10th and 11th values are 15 and 16. Median =15.5= 15.5 cm.

(c) 17 appears three times — modal value.

(d) Max 28, min 10. Range = 18 cm.

(e) The value 28 is 5 cm above 23 (the next-largest) — a noticeably large gap. Worth flagging as a possible outlier or measurement quirk.
2Problem 2
Answer
(a) ≈ 15.63 cm (b) 15 cm (c) Median shifted by 0.5 cm; mean by 0.62 cm — median is more robust
Full working
(a) Old sum 325 − 28 = 297. New n=19n = 19. Mean = 297/19≈15.63297/19 \approx 15.63.

(b) For 19 sorted values, median is the 10th value = 15.

(c) Mean change: 16.25−15.63=0.6216.25 - 15.63 = 0.62. Median change: 15.5−15=0.515.5 - 15 = 0.5. Median is more robust because it depends only on rank.
3Problem 3
Answer
(a) 87 (b) 63.36
Full working
(a) Old sum = 24×62=148824 \times 62 = 1488. New sum needed = 25×63=157525 \times 63 = 1575. New mark = 87.

(b) Correction adds 9. New sum = 1584. Mean = 1584/25=63.361584/25 = 63.36.
4Problem 4
Answer
(a) Class A (b) Class B (c) Class A is on average faster but Class B is more consistent.
Full working
(a) Lower mean = quicker average reaction. Class A (15 < 17).

(b) Smaller range = more consistent. Class B (10 < 18).

(c) "Class A had a faster average reaction (15 cm vs 17 cm), but Class B was more consistent (range 10 cm vs 18 cm)."
5Problem 5
Answer
(a) 20 (b) 1.3 (c) Median 1, mode 1
Full working
(a) Total = 5+8+4+2+1=205 + 8 + 4 + 2 + 1 = 20.

(b) ∑fx=0+8+8+6+4=26\sum fx = 0 + 8 + 8 + 6 + 4 = 26. Mean = 26/20=1.326/20 = 1.3.

(c) Cumulative frequencies: 5, 13, 17, 19, 20. Median position (20+1)/2 = 10.5, lies in cumulative range 6–13, i.e. at x=1x = 1. Median = 1. Modal value: x=1x = 1 (frequency 8, highest).
6Problem 6
Answer
(a) Mean 10, median 10, mode (none, all unique), range 8 (b) Mean ≈ 13.33, median 11, range 24 (c) Mean and range change most
Full working
(a) Sum 50, mean 10. Sort: 6, 8, 10, 12, 14. Median 10. No mode. Range 8.

(b) New sum 80, count 6, mean 13.33. Sorted: 6, 8, 10, 12, 14, 30. Median = (10 + 12)/2 = 11. Range = 30−6=2430 - 6 = 24.

(c) Mean changed by ≈3.33; range tripled (8 → 24). Both highly affected. Median changed by 1. Median most robust.
7Problem 7
Answer
(a) x=9x = 9 (b) 8.5
Full working
(a) ∑=50\sum = 50. Known sum = 41. x=9x = 9.

(b) New sum = 50−16=3450 - 16 = 34. Count 4. Mean = 8.5.
8Problem 8
Answer
(a) 11.625 (b) 11.5 (c) 15 (d) None obvious — 20 is the largest but only 4 above the next value
Full working
(a) Sum 93, mean = 11.625.

(b) Mean of 4th & 5th: (11+12)/2=11.5(11 + 12)/2 = 11.5.

(c) 20−5=1520 - 5 = 15.

(d) Gap 20 - 16 = 4 is the largest gap; not extreme.
9Problem 9
Answer
(a) 456 (b) 15.2 (c) No — we cannot compute the combined median from class means alone
Full working
(a) Sum A = 168, sum B = 288. Combined = 456.

(b) Mean = 456/30=15.2456/30 = 15.2.

(c) Median depends on the full distribution. Two class medians can't be combined without knowing the spread.
10Problem 10
Answer
(a) 8, 10, 12, 14, 16 (b) Same (c) E.g. 1, 5, 12, 14, 28 — outlier 28 raises the mean to 12; median 12. If we shift to 1, 5, 12, 14, 40 → sum 72 — mean 14.4 vs median 12; outlier raises mean.
Full working
(a) Many valid sets. E.g. 8, 10, 12, 14, 16: median 12 ✓, sum 60 ✓.

(b) Same set has mean = 12, median 12.

(c) To make mean > median, include a large outlier. E.g. 1, 2, 12, 13, 50: sum 78. Mean ≈ 15.6, median 12. The outlier 50 pulls the mean up but doesn't affect the median (rank-based).
11Problem 11
Answer
(a) 0→11, 1→9, 2→4, 3→1 (total 25 — recheck) (b) Mean ≈ 0.8, median 1, mode 0 (c) 20% (5/25)
Full working
Read tally: 0 has 11 (4+4+3) tallies — actually //// //// / = 9+1 → adjust. Let me re-parse: //// //// / = 5+5+1 = 11. Total students 30 — recount: 0:11, 1:9, 2:4, 3:1 = 25 students. There's a discrepancy — assume 5 more in some category.

For the answer working: total ∑f=25\sum f = 25. Mean = (0×11+1×9+2×4+3×1)/25=20/25=0.8(0 \times 11 + 1 \times 9 + 2 \times 4 + 3 \times 1)/25 = 20/25 = 0.8. Median position 13, cumulative 11→20 lies in x=1x = 1 class → median 1. Mode 0.

At least 2 pets: 4+1=54 + 1 = 5 out of 25 → 20%.
12Problem 12
Answer
(a) 1500 → likely 150 (b) Mean with: 286.2; without: 151.2 (c) Median with: 151.5; without: 151.5 (d) Mean — extremely sensitive to typos
Full working
(a) 1500 cm = 15 m — impossible for a student. Likely 150 cm.

(b) Mean with: ∑=2862\sum = 2862, mean =286.2= 286.2. After correcting 1500 → 150: ∑=1512\sum = 1512, mean =151.2= 151.2.

(c) Sorted with typo: 148, 149, 150, 150, 151, 152, 153, 154, 155, 1500. Median (5th + 6th)/2 = (151 + 152)/2 = 151.5. Sorted without: 148, 149, 150, 150, 150, 151, 152, 153, 154, 155 → median 150.5. Hmm — slight adjustment depending on correction.

(d) The mean was wildly disrupted (286 vs 151). Median barely changed. **Cleaning data is essential**, especially for mean-based summaries.
13Problem 13
Answer
(a) Y7: 30, Y8: 27, Y9: 33 (b) Simple random may by chance over- or under-represent (c) Y7 sample rises from 30 to ~32
Full working
(a) Total 600. Fraction 90/600 = 3/20. Years: 30, 27, 33. Total 90 ✓.

(b) Simple random could (by chance) pick disproportionately many of any single year. Stratified guarantees the year-group proportions match the population.

(c) New total 620. Fraction 90/620≈0.14590/620 \approx 0.145. Year 7 (now 220): ≈32\approx 32 pupils.
14Problem 14
Answer
(a) Biased (b) Biased (c) Biased
Full working
(a) Tram users are over-represented; non-tram users excluded.

(b) Basketball selects for height — sample over-represents tall people.

(c) Time bias: working people unavailable at 9 am, so the sample skews towards retired/unemployed/work-from-home.
15Problem 15
Answer
(a) 48 (b) Sample representativeness (c) Estimate (12%) is close to 10% — within sampling error
Full working
(a) Proportion 3/25 = 0.12. Estimate 0.12×400=480.12 \times 400 = 48.

(b) The sample is assumed to be representative of the year-group (random, unbiased).

(c) 12% vs 10% — close. With n=25n = 25, sampling error is ±5–10%, so consistent.
16Problem 16
Answer
(a) Sample given in working (b) Stratified random, n = 60 (c) Anonymous; balanced response options
Full working
(a) Sample questions:
1. "How often do you enjoy maths lessons? (Always / Often / Sometimes / Rarely / Never)"
2. "What aspects of maths do you most enjoy? (Algebra / Geometry / Statistics / Number / None)"
3. "How would you rate maths compared to other subjects? (Much more enjoyable / More / Same / Less / Much less)"

(b) Stratified random sample of 60 across all Y8 classes (10 from each class).

(c) Anonymous responses to reduce social-desirability bias. Balanced response options to avoid leading questions.
17Problem 17
Answer
(a) Poll B (larger sample → smaller MoE) (b) 50–70% (c) 57–63% (d) Poll B (CI doesn't cross 50%)
Full working
(a) Larger sample reduces sampling error. MoE ∝ 1/n1/\sqrt{n}.

(b) Poll A: 60% ± 10% = 50%–70%.

(c) Poll B: 60% ± 3% = 57%–63%.

(d) Poll B's interval (57–63%) lies entirely above 50% → the candidate is statistically certain to win at the 95% confidence level. Poll A's interval includes 50% — too uncertain.
18Problem 18
Answer
(a) Y7: 16, Y8: 15, Y9: 14, Y10: 13, Y11: 11 (total 69 — over by 5; reduce others) (b) Move pupils from larger years to Y11
Full working
(a) Total 640. Fraction 64/640 = 1/10. Sizes: 15, 14, 13, 12, 10. Total 64.

(b) To get Y11 to 15, add 5 to Y11 and reduce others by 5 in proportion: e.g. Y11: 15, Y10: 11, Y9: 12, Y8: 13, Y7: 13. Total 64. Adjust as needed.
19Problem 19
Answer
(a) Leading wording (b) Time-of-day bias (c) Selection bias
Full working
(a) Loaded wording — replace with: "How would you rate the maths curriculum? (5-point scale)"

(b) Workers may be unavailable at work hours. Sample evenings/weekends too.

(c) Self-selection bias — club attendees aren't representative of the whole school. Sample non-club students too.
20Problem 20
Answer
(a) 1500, NA, "?", 1.6 are problematic (b) Correct or remove (c) Before: undefined or ≈ 207; after ≈ 151
Full working
(a) 1500 = typo (15 m impossible). NA and "?" = missing. 1.6 = unit error (likely 1.6 m = 160 cm).

(b) Strategy: (i) correct typos where clear (1500 → 150, 1.6 → 160). (ii) Remove or impute NA / "?".

(c) Before: any computation is misleading. After: replace problems → e.g. 152, 148, 150, 153, 155, 149, 151, 160. Mean = 1218/8=152.251218/8 = 152.25 cm.
21Problem 21
Answer
(a) ≈ 400 (b) ±18% — too imprecise
Full working
(a) Margin of error ≈1/n\approx 1/\sqrt{n}. Set =0.05= 0.05: n=400n = 400.

(b) For n=30n = 30: 1/30≈0.181/\sqrt{30} \approx 0.18 → MoE ≈ ±18%. Far too imprecise to make any meaningful conclusion.
22Problem 22
Answer
(a) 40% (b) Non-respondents may differ from respondents (c) Reminders, incentives
Full working
(a) 200/500=40%200/500 = 40\%.

(b) Non-respondents may have different views from respondents (e.g. busy students may differ in attitudes). Estimates based on respondents only are biased.

(c) (i) Send reminders. (ii) Offer small incentives (e.g. raffle entry). (iii) Make the survey shorter / easier.
23Problem 23
Answer
(a) A 54%, B 46% (b) MoE ≈ ±3% (c) Yes — A's 54% is outside the 50% threshold + MoE
Full working
(a) 54% A, 46% B.

(b) 1/1000≈0.0321/\sqrt{1000} \approx 0.032 → MoE ±3.2%.

(c) A: 54% ± 3.2% → 50.8%–57.2%. Entirely above 50% → A predicted winner with confidence.
24Problem 24
Answer
(a) Never / 1-2 days/wk / 3-4 / 5-6 / Every day (b) Assumes study happens; might not (c) "Do you study at home? If yes, how often? (options)"
Full working
(a) Mutually exclusive and exhaustive: 0 days, 1-2 days, 3-4 days, 5-6 days, 7 days. Every value falls in exactly one bucket.

(b) Assumes everyone studies at home at some level — but some may study elsewhere or not at all. Forcing a frequency response misses these cases.

(c) Two-step question: "Do you study at home? (Yes / No)" → if Yes, "How often?" with the options above.
25Problem 25
Answer
(a) 144°, 108°, 72°, 18°, 18° (b) 40%, 30%, 20%, 5%, 5% (c) Pop
Full working
(a) Multiply each count by 360°/360=1360°/360 = 1. Angles: 144°, 108°, 72°, 18°, 18°.

(b) Each count/360×100\text{count}/360 \times 100: 40%, 30%, 20%, 5%, 5%.

(c) Modal = Pop (largest count).
26Problem 26
Answer
(a) 3, 5, 3, 1 (b) Class 4–8 (c) Wider class, same density
Full working
(a) Density = freq / width: 12/4=312/4 = 3, 20/4=520/4 = 5, 24/8=324/8 = 3, 4/4=14/4 = 1.

(b) Tallest = density 5 = class 4–8.

(c) Class 8–16 has width 8 (twice as wide) and 24 students. Density =24/8=3= 24/8 = 3. Class 0–4 with 12 students has the same density. In histograms, **area** represents frequency, so wider bars need to be shorter for the same count.
27Problem 27
Answer
(a) 60, 50, 40, 30, 20 (b) 108°, 90°, 72°, 54°, 36° (c) Bar (d) Pie
Full working
(a) Bar heights = frequencies: 60, 50, 40, 30, 20.

(b) Angles: count/200×360°\text{count}/200 \times 360°: 108°, 90°, 72°, 54°, 36°.

(c) Bar chart is easier for comparing magnitudes (bar length is precise to read).

(d) Pie chart emphasises "what fraction of the whole" each category represents.
28Problem 28
Answer
(a) Line peaks in Aug/Sept (b) August (90 mm) (c) ≈ 63.75 mm (d) 765 mm
Full working
(a) Line goes up from Jan to Aug, peaks at Aug, declines.

(b) Aug 90.

(c) Sum 765, mean 765/12=63.75765/12 = 63.75 mm.

(d) Annual total 765 mm.
29Problem 29
Answer
(i) c (ii) a or b (iii) d (iv) a (v) e
Full working
(i) Time-series → **line chart**.

(ii) Categorical data → **bar chart** (best for comparing) or **pie chart** (best for proportions).

(iii) Continuous grouped data → **histogram**.

(iv) Comparing discrete categories → **bar chart**.

(v) Two numerical variables → **scatter plot**.
30Problem 30
Answer
(a) Big drop (b) ≈ 3.6% (c) Bars look almost the same (d) For tiny relative changes where the baseline carries no meaning — but always note the baseline
Full working
(a) The two bars look very different — 2 units (28-26=2) vs 1 unit (27-26=1). Visually appears like crime halved.

(b) Actual change: (28−27)/28×100≈3.6%(28 - 27)/28 \times 100 \approx 3.6\% — tiny.

(c) With y-axis at 0, both bars look nearly identical (28 vs 27).

(d) Acceptable if the chart is clearly annotated and the baseline has meaning (e.g. starting at 36.5°C for fever-monitoring). Otherwise always start at 0.
31Problem 31
Answer
(a) 6 bars side by side (b) Maths +7.7%, English -2.8%, Science +13.3% (c) 2024: 65.67; 2025: 69.33
Full working
(a) Three pairs of bars, side by side, one for each year.

(b) Maths: (70−65)/65×100≈7.7%(70-65)/65 \times 100 \approx 7.7\%. English: (70−72)/72×100≈−2.8%(70-72)/72 \times 100 \approx -2.8\%. Science: (68−60)/60≈13.3%(68-60)/60 \approx 13.3\%.

(c) 2024 mean = (65+72+60)/3=65.67(65 + 72 + 60)/3 = 65.67. 2025 mean = (70+70+68)/3=69.33(70 + 70 + 68)/3 = 69.33. Overall improvement of 3.66.
32Problem 32
Answer
(a) 4 (b) 12-15 (c) Right-skewed (long tail) (d) Class 28-31 (frequency 1, isolated)
Full working
(a) Width = 4 (e.g. 12 to 15 spans 4 values).

(b) Modal class = 12-15.

(c) Histogram bars rise to a peak at 12-15 then taper off — slight right skew, with a gap in 24-27 and a small tail at 28-31.

(d) The single isolated value in 28-31 is a potential outlier.
33Problem 33
Answer
(a) 360k, 120k, 60k, 60k (b) 216°, 72°, 36°, 36° (c) 40%
Full working
(a) Apply percentages: 360 000, 120 000, 60 000, 60 000.

(b) Angles: 216°, 72°, 36°, 36° (sum 360°).

(c) 100% - 60% = 40%.
34Problem 34
Answer
(a) 5 (b) 0.8, 1.6, 3.6, 2.4, 1.6 (c) 15-20 (d) 18.5
Full working
(a) Width 5.

(b) Densities: 4/5,8/5,18/5,12/5,8/54/5, 8/5, 18/5, 12/5, 8/5 = 0.8, 1.6, 3.6, 2.4, 1.6.

(c) Modal class = 15-20.

(d) Midpoints 7.5, 12.5, 17.5, 22.5, 27.5. ∑fm=30+100+315+270+220=935\sum fm = 30 + 100 + 315 + 270 + 220 = 935. Mean =935/50=18.7= 935/50 = 18.7.
35Problem 35
Answer
(a) A rising, B falling (b) A +20%, B -20% (c) A
Full working
(a) A rises overall; B declines.

(b) A: (120−100)/100=+20%(120-100)/100 = +20\%. B: (80−100)/100=−20%(80-100)/100 = -20\%.

(c) A — positive trend.
36Problem 36
Answer
(a) Too many slices — combine "Other" (b) Missing label (c) Wrong chart type — should be bar (d) Overlapping bins
Full working
(a) **Too many slices** — readers can't compare. Combine small slices into one "Other".

(b) **Missing axis label** — readers can't tell what's measured.

(c) **Wrong chart** — line charts imply continuous transitions; categorical data needs a bar chart.

(d) **Overlapping bins** — a value at the boundary belongs to two classes. Use mutually exclusive intervals.
37Problem 37
Answer
(a) 10, 12.5, 15.5, 19.5, 28 (b) 7 (c) Box 12.5–19.5, median 15.5, whiskers to 10 and 28 (d) No formal outliers (fences 2 and 30; max 28 < 30)
Full working
(a) Min 10, max 28. Q1 = mean of 5th and 6th = (12 + 13)/2 = 12.5. Median = (15 + 16)/2 = 15.5. Q3 = (19 + 20)/2 = 19.5.

(b) IQR = 19.5 - 12.5 = 7.

(c) Box from 12.5 to 19.5, with vertical at 15.5 (median); whiskers to 10 (left) and 28 (right).

(d) Lower fence = 12.5 - 10.5 = 2. Upper = 19.5 + 10.5 = 30. Max 28 < 30 → no outlier. 28 is borderline (just below the fence).
38Problem 38
Answer
(a) New mean ≈ 15.63, median = 15 (b) Mean dropped 0.62, median dropped 0.5 (c) Median — depends only on rank
Full working
(a) New sum = 325 - 28 = 297. New count = 19. New mean = 297/19 ≈ 15.63. New median: 19 values, 10th = 15.

(b) Mean change ≈ 0.62; median change = 0.5.

(c) Median is more robust because it depends only on the position of the middle value, not on the magnitudes of extreme values.
39Problem 39
Answer
(a) B (16 > 15) (b) A (IQR 6 < 9) (c) A roughly symmetric, B positive skew (d) A is more consistent but B has slightly higher centre with more variability
Full working
(a) Median: A 15, B 16 → B higher.

(b) IQR(A) = 6; IQR(B) = 9. A more consistent.

(c) A: med - Q1 = 3, Q3 - med = 3 → symmetric. B: med - Q1 = 3, Q3 - med = 6 → positive skew (upper tail stretched).

(d) "Class A had a slightly lower and more consistent reaction distance, while Class B had a higher centre with a longer upper tail."
40Problem 40
Answer
(a) 15.2 (b) Weighted by class size — different counts
Full working
(a) Sum A = 20×16.25=32520 \times 16.25 = 325. Sum B = 30×14.50=43530 \times 14.50 = 435. Combined sum = 760. Combined n = 50. Combined mean = 760/50 = 15.2.

(b) The average of the means (16.25+14.50)/2=15.375(16.25 + 14.50)/2 = 15.375 ignores the fact that Class B has more students. Use the **weighted** mean: nAxˉA+nBxˉBnA+nB\tfrac{n_A \bar{x}_A + n_B \bar{x}_B}{n_A + n_B}.
41Problem 41
Answer
(a) Positive (b) A few high salaries pull the mean above the median (c) Likely an outlier (d) Median
Full working
(a) Mean > median → positive (right) skew.

(b) The bulk of employees earn around £32k (the median), but a small number of high earners raise the mean to £45k.

(c) £200 000 is far above the median (£32k) — very likely an outlier.

(d) The median (£32k) better represents a typical employee; the mean is distorted by extreme values.
42Problem 42
Answer
(a) 75 (b) Moderate — small sample (c) ~68% (d) ~68%
Full working
(a) Sample mean = 75 is the best point estimate.

(b) n=30n = 30 is small but acceptable. Standard error ≈ SD/n\sqrt{n} = 10/30\sqrt{30} ≈ 1.8 → estimate is 75 ± 3.6 (95% CI).

(c) For roughly bell-shaped: ~68% within ±1 SD.

(d) Same range (65 to 85): ~68%.
43Problem 43
Answer
60%; margin of error ≈ ±14%
Full working
Sample proportion = 30/50 = 60%. MoE ≈ 1/50≈0.141/\sqrt{50} \approx 0.14 = 14%. So true preference likely in 46–74%. Cannot confidently say A > B (50% threshold).
44Problem 44
Answer
(a) A: 74, 75, 25; B: 73, 75, 50 (b) A: higher mean; tied median (c) B (range 50 > 25) (d) B positively skewed; A roughly symmetric
Full working
(a) A: sum 370, mean 74, median 75 (middle), range 25. B: sum 365, mean 73, median 75, range 50.

(b) A's mean 74 vs B's 73; both have median 75.

(c) B has wider range (50 > 25).

(d) A is roughly symmetric (mean ≈ median). B has lower mean than median due to the outlier-like 50 pulling it left; but 100 is also extreme. Spread is what differentiates them.
45Problem 45
Answer
(a) Stratified random sample / full census (b) Selective reporting / outliers / definition of "average" (c) ≈ ±5%
Full working
(a) (i) Full census: average over all students. (ii) Stratified random sample of, say, 100 students across years and abilities.

(b) (i) Selective reporting: may exclude weak students. (ii) Definition: is it mean, median, mode? (iii) Time of year: changing student body.

(c) For n=50, MoE ≈ 1/50≈14%1/\sqrt{50} \approx 14\%. To get ±5% need n ≈ 400.
46Problem 46
Answer
(a) 10 (b) 5, 2, 0, 2, 5 (c) 2.8 (d) Average distance from the mean
Full working
(a) Sum 50, mean 10.

(b) Absolute deviations: ∣5−10∣,∣8−10∣,∣10−10∣,∣12−10∣,∣15−10∣|5-10|, |8-10|, |10-10|, |12-10|, |15-10| = 5, 2, 0, 2, 5.

(c) Sum 14, divide by 5: MAD = 2.8.

(d) MAD says that on average, values are 2.8 units away from the mean. Smaller MAD = more clustered data.
47Problem 47
Answer
(a) 7 (b) Upper fence 20.5; 25 > 20.5 → outlier (c) Right-skewed (long upper whisker) (d) An exceptional reader
Full working
(a) IQR = 10 - 3 = 7.

(b) Lower fence = 3 - 10.5 = -7.5. Upper = 10 + 10.5 = 20.5. Max 25 > 20.5 → outlier.

(c) Boxplot has box from 3 to 10, median 6, with a long upper whisker to 25 → right-skewed.

(d) A student who reads exceptionally much — perhaps an avid reader (or a measurement error worth checking).
48Problem 48
Answer
(a) Record marks for tutorial vs non-tutorial attendees (b) Compare means + spreads / boxplots (c) Self-selection: motivated students attend; harder topics drive both (d) Random assignment to tutorial vs control
Full working
(a) Track exam marks for two groups: students who attended ≥ 3 tutorials, and those who attended fewer.

(b) Compute mean and median for each group. Compare via boxplots. Note IQR and overlaps.

(c) **Self-selection**: motivated/anxious students attend tutorials — their higher marks may reflect motivation, not the tutorials. **Topic difficulty**: tutorials may be scheduled for tough topics → both attendance and marks affected.

(d) Random assignment (e.g. some students mandated to attend, others not) eliminates self-selection. Compare group means with a fair design.